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2 years ago

How do I solve this? (please help to find what goes in the boxes as well)

Mathematics

1 answer:

natta225 [31]2 years ago

5 0

Answer:

First Box: Factor by difference of squares

Second Box: It has all perfect squares

Third Box: see my work

Step-by-step explanation:

We have the equation $4x^2=36$

Before we do anything, let us bring all of the terms to the left side

$4x^2-36=0$

Now that we have moved the terms to one side, it is clear that we have a difference of squares.

-Work-

$4x^2=36\\\\4x^2-36=0\\\\(2x+6)(2x-6)=0\\\\$

$2x+6=0\\\\2x=-6\\\\x=-3$

$2x-6=0\\\\2x=6\\\\x=3$

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3 years ago

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Step-by-step explanation:

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2 years ago

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Fiona wrote the linear equation y = 2/5 x – 5. When Henry wrote his equation, they discovered that his equation had all the same

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we have

$y=\frac{2}{5}x-5$

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$5y=4x-25$

Divide by $5$ both sides

$y=\frac{4}{5}x-5$

therefore

the case A) is not equal to Fiona's equation

case B) $x-\frac{5}{2}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-10y= 25$

$10y=4x-25$

Divide by $10$ both sides

$y=\frac{2}{5}x-2.5$

therefore

the case B) is not equal to Fiona's equation

case C) $x-\frac{5}{4}y= \frac{25}{2}$

Multiply by $4$ both sides

$4x-5y= 50$

$5y=4x-50$

Divide by $5$ both sides

$y=\frac{4}{5}x-10$

therefore

the case C) is not equal to Fiona's equation

case D) $x-\frac{5}{2}y= \frac{25}{2}$

Multiply by $2$ both sides

$2x-5y= 25$

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Divide by $5$ both sides

$y=\frac{2}{5}x-5$

therefore

the case D) is equal to Fiona's equation

<u>the answer is</u>

$x-\frac{5}{2}y= \frac{25}{2}$

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