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Tpy6a [65]
3 years ago
12

Compute 33(0.5) - 6(0.5) - 7/2.

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0
= 33 * 0.5 - 6 * 0.5 - 3.5

= 16.5 - 3 - 3.5

= 10 Answer
lora16 [44]3 years ago
5 0
Hi there! The answer is 10.

33(0.5) - 6(0.5) -  \frac{7}{2}
We can use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Since we cannot work inside the parenthesis in this question and since we don't have exponents, we can move on to multiplying.
16.5 - 3 -  \frac{7}{2}

Our next step would be subtracting. To make the process of subtracting some easier, I'll first change the fraction into a decimal.
16.5 - 3 - 3.5

Finally subtract.
13.5 - 3.5 = 10

The answer is 10.
~ Hope this helps you!
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On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl
kondor19780726 [428]

Answer:

0.40

Step-by-step explanation:

Members who run only  long distance = 8%

So, probability that a member will run only long distance = P(A) = 0.08

Members who compete only in field events = 32%

So, probability that a member will compete only in field events = P(B) 0.32

Members who are sprinters = 12%

So, probability that a member is sprinter = P(C) 0.12

We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:

P(A or B) = P(A) + P(B)

Using the values, we get:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40

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What is 2/5 + 3/7 in the LCD way
agasfer [191]
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Step-by-step explanation:

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