Answer:
A linear algebraic equation is nice and simple, containing only constants and variables to the first degree (no exponents or fancy stuff). To solve it, simply use multiplication, division, addition, and subtraction when necessary to isolate the variable and solve for "x". Here's how you do it: 4x + 16 = 25 -3x =
Answer:
n = -6
x = -7
n = 27
Step-by-step explanation:
Question 1
-3n - n + 12 = 36
First we get all the variables to one side using subtraction property of equality.
-3n - n + 12 (-12) = 36 (-12)
-4n = 24
divide by the coefficient of n to isolate the variable
-4n/-4 = 24/-4
n = -6
Question 2
-2x - 3x - 15 = 20
-5x - 15 = 20
-5x = 35
x = -7
Question 3
3 + n/9 = 6
Isolate the n variable
n/9 = 6 - 3
multiply by 9
n = 27
Answer:
m∠1 = 100°
Step-by-step explanation:
You buy 3 shirts and 1 pair of pants for $32. Your friend buys 2 shirts and 3 pairs of pants for $40. How much did each item cost?
First let’s define a shirt as X and pants as Y!
In the first scenario, the equation will be 3X + Y =$32
In the second scenario, the equation will be 2X + 3Y = $40
Now because we have two different variables (X & Y) let’s solve for one of them (Ex: Y) to simplify the equations!
3X + Y= $32—> subtract 3X on both sides of the equation
-3X. - 3X
Net result: Y= 32- 3X
Now we can insert this into the second equation 2X + 3Y = $40 in order to solve for X variable
2X + 3(32-3X) = $40
2X + 96 - 9X = $40 —> simplify the equation
-7X + 96 = $40 —> substrate 96 from both sides
-7X = -56 —> divide both sides by -7
X= 8
Now reinsert 8= X into 3X + Y = $32
3(8) + Y = $32
24+ Y = $32 —> substract 24 from both sides
y = 8
ANSWER: X= 8, Y= 8
If I am wrong I am sorry >_<