Answer:
(3, 4 )
Step-by-step explanation:
5x + 3y = 27 → (1)
2x + y = 10 ( subtract 2x from both sides )
y = 10 - 2x → (2)
substitute y = 10 - 2x into (1)
5x + 3(10 - 2x) = 27
5x + 30 - 6x = 27
- x + 30 = 27 ( subtract 30 from both sides )
- x = - 3 ( multiply both sides by - 1 )
x = 3
substitute x = 3 into (2)
y = 10 - 2(3) = 10 - 6 = 4
solution is (3, 4 )
Step-by-step explanation:
here ,
now,
cosec(2-45°)=2
or,
1/sin(2-45°) =2
or,
1/sin2cos45°-cos2sin45=2
or,
or,
sorry I have that much qualifications to work on this question and hoping this much will make bit easy for you to solve it further
X+y=62 ; x-y=12 Solve for x in one equation and plug that value into the other equation. ===> x=12+y ; 12+y+y=62 Subtract 12 to both sides (2y=50), then divide by 2 to find y (y=25). Now, plug 25 as y into x=12+y, getting x=37. Your two numbers are 37 and 25.
0 = 0
The input is an identity: it is true for all values
