Can somebody help me please
2 answers:
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Answer:
A system of linear equations will have exactly one point of intersection, for example:
2x+y=5
-x+y=2
However, a system of linear equations with no solution will have no points of intersection, for example:
-4x+10y=6
2x-5y=3
Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe
And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)
I attached a photo below, and one of how to graph it
the values of x are -7/5 and -7/8 .
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid