All categories

2 years ago

Find the slope of the line that passes through (8, 6) and (2, 7).

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

6 0

Vas happenin!!

Slope form - y2-y1/x2-x1

7-6/ 2-8

1/-6

Your slope is -6x

Hope this helps

-Zayn Malik

You might be interested in

What are the coordinates of a point in quadrant ||| which is 8 units away from point p Answer quick

trapecia [35]

Answer:

If it is at -8, -8 then p is at 0,0

Step-by-step explanation:

Sorry, there is not much information given to answer.

5 0

2 years ago

Write the equation of a line in slope-intercept form that goes through the points

Stella [2.4K]

Answer: The equation in slope-intercept form is y=2x-11

Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.

Hope this helps!

5 0

2 years ago

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

2 years ago

Read 2 more answers

Which set of points represents a function?

Greeley [361]

Answer:

the 0,2 does beautiful as it comes

4 0

2 years ago

Can someone help me please!

erica [24]

9514 1404 393

Answer:

B, C, E

Step-by-step explanation:

Distributing the minus sign in the given expression results in ...

6x +1 -3x -(-1)

6x +1 -3 +1 . . . . simplify

The two expressions that show the constant terms as +1 - 1 are erroneous. The two constant terms are +1 -(-1) or +1 +1.

The correct expressions are the 2nd, 3rd, and 5th ones (b, c, e).

5 0

2 years ago