10 students (brass)=40% of band
4 students (strings)=16% of band
? students (other)=44% rest of band
14/56%=?/44%
(cross multiply to find ?){don't forget to turn percents into decimals}
?=11
There are 25 students in total in the band.
4x+6=12
4x=12-6
4x=6
4x/4=6/4
X=1.5
Answer:
Step-by-step explanation:
It's two unequal real solutions.
a = 1
b = 7
c = 6
discriminate = sqrt(7^2 - 4*1*6)
discriminate = sqrt(49 - 24)
discriminate = sqrt(25)
discriminate = 5
Now you cannot determine what this means unless you put it in the quadratic formula
x = (-7 +/- 5)/2
x = (- 7 + 5) / 2
x = - 2/2 = - 1
x = (-7 - 5)/2
x = -12/2
x = - 6
You see that you have two unequal reals.
Answer:
Hi there!
Your answer is:
The smaller integer is -6
The larger integer is -5
Step-by-step explanation:
Two consecutive integers:
x, x+1
Product= multiply
(x) × (x+1) = x^2 - 6
x^2 + x= x^2 -6
-x^2
x= -6
Plug back in
First integer (smaller):
-6
Second integer (larger):
-6+1
-5
<u>Check</u><u> </u><u>your </u><u>work</u><u>!</u>
(-6) × (-6+1)
(-6)× (-5)
30 = (-6)^2 -6
30 = 36-6
30= 30 ✓✓✓✓
That's how we determine that <em>this </em><em>is</em><em> </em><em>the</em><em> </em><em>corr</em><em>ect</em><em> </em><em>answe</em><em>r</em>
Hopefully this helps
Answer:
The surface area of the model pyramid is 
Step-by-step explanation:
we know that
The surface area of the pyramid is equal to
where
B is the area of the base of the pyramid
LA is the lateral surface of the pyramid
<em>Find the area of the base B</em>
-----> is a square
<em>Find the lateral surface area of the pyramid LA</em>
we know that
The lateral surface area is equal to the area of its four triangular faces
![LA=4[\frac{1}{2}(11)(15)]=330\ in^{2}](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2811%29%2815%29%5D%3D330%5C%20in%5E%7B2%7D)
<em>Find the surface area of the pyramid</em>
Substitute the values
