With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that
![I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx](https://tex.z-dn.net/?f=I%20%3D%20%5Cdisplaystyle%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7B%5Csqrt%5B%5Cphi%5D%7Bx%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7B%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx%20%3D%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7Bx%5E%7B%5Cphi-1%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7Bx%20%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx)
Replace
:

Split the integral at x = 1. For the integral over [1, ∞), substitute
:

The integrals involving tan⁻¹ disappear, and we're left with

Answer:
Following are the responses to the given choices:
Step-by-step explanation:
In step 1:
State the zero and alternate test hypotheses. Insert underneath.
Smaller companies in their region are and they spend at least 24 hours per week on the marketing of the these companies
There really is no growth for smaller firms in their area because the companies spend or less 24 hours per week on marketing.
In step 2:
Each test statistics meaning is calculated. Around two decimal places for your reply.
In step 3:
Draw a start and write the decision.
Since it is observed that
it is then concluded that the null hypothesis is rejected.
Consequently we consider that small companies in their field may not expand, as they spend or less 24 hours per week on marketing.
Anytime x = 0 in a point the y intercept is immediately defined.
y = mx + b The y intercept is b
y = 0 + b
0 = 0 + b
b = 0
What you know so for is
y = mx + b
y = mx since b = 0
7 = m*1
m = 7
The answer is y = 7x <<<<<<Answer.
Answer:
The relator recived $8,186.4
Step-by-step explanation:
What you have to do is find the 60% of the commission. Commission is 4% of $341,100 (100%)
First do a cross multiplication to find 4% of $341,100
100% ___ $341,100
4%______x:

So, the 4% of $341,100 is $13,466
Now you have to find the 60% of $13,466
100% ___ $13,466
60%______x:

The answer is: $8,186.4