Question

What is a5 in the sequence defined as follows? an = 5x2^(n-1)

Answer 1

Given:

The nth term of the sequence is defined as $a_n=5\times 2^{n-1}$

We need to determine the term $a_5$ of the sequence.

The term $a_5$:

The term $a_5$ can be determined by substituting n = 5 in the nth term of the sequence $a_n=5\times 2^{n-1}$

Thus, we get;

$a_5=5\times 2^{5-1}$

Simplifying the expression, we get;

$a_5=5\times 2^{4}$

Squaring the term, we have;

$a_5=5\times 16$

Multiplying the expression, we get;

$a_5=80$

Thus, the value of the term $a_5$ of the sequence is 80.