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ss7ja [257]
3 years ago
14

Determine whether the polynomial below can be factored into perfect squares. If so, factor the polynomial. Otherwise, select tha

t it cannot be factored into a perfect square.

Mathematics
2 answers:
kifflom [539]3 years ago
5 0

Answer:

Option A. (9x - 12)²

Step-by-step explanation:

We will factorize the given polynomial into perfect square.

The polynomial is 81x²- 216x + 144

We will take 9 common out of this polynomial first

81x² - 216x + 144 = 9(9x² - 24x + 16)

= 9[(3x)² - 2(3)(4)x + 4²]

= 9[(3x - 4)²

= 3²(3x - 4)²

= (9x - 12)²

Therefore, Option A. (9x - 12)² is the answer.

kkurt [141]3 years ago
3 0

Answer:

A. =(9x-12)^2

Step-by-step explanation:

We need to determine whether the polynomial 81x^2-216x+144 can be factored into perfect squares. If so, factor the polynomial. Otherwise, select that it cannot be factored into a perfect square.

81x^2-216x+144

=9(9x^2-24x+12)

=9(9x^2-12x-12x+12)

=9(3x(3x-4)-4(3x-4))

=9(3x-4)(3x-4)

=9(3x-4)^2

=3^2(3x-4)^2

=(3(3x-4))^2

=(9x-12)^2

Hence choice A. =(9x-12)^2 is correct.

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Coby sells apples and bananas at his fruit store. He charges $6 for a bunch of bananas, and $8 for a pound of apples. If a custo
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Answer:

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Step-by-step explanation:

We have to assume that a "piece of fruit" is either a bunch of bananas or a pound of apples. Without that assumption, there is insufficient information to work the problem.

Let B represent the number of bunches of bananas. Then 13-B is the number of pounds of apples. The total cost is ...

  6B +8(13 -B) = 92

  -2B + 104 = 92 . . . . . eliminate parentheses

  B = -12/-2 = 6 . . . . . . subtract 104, then divide by the coefficient of B

  13-B = 7 . . . . . . . . . . . the number of pounds of apples

The customer bought 6 bunches of bananas and 7 pounds of apples.

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<em>Comment on the solution</em>

You will note that finding the value of the variable involved arithmetic with negative numbers. If you want the numbers to stay positive, then you can choose the variable to represent <em>the most expensive</em> of the items: the number of pounds of apples.

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let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
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(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

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Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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