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Nady [450]
3 years ago
11

Abby uses base 10 blocks to show 1,109. She has no thousands cubes and only 9 flats, as shown. Draw longs and units on the chart

to finish Abby's model.
Mathematics
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

  20 longs, 9 units more than the 9 flats

Step-by-step explanation:

If Abby has 9 flats, she has 900 blocks of the 1109 she needs. The remaining 209 can be represented by ...

  20 longs

  9 units

_____

<em>Comment on the question</em>

We cannot see the model Abby has put together so far, so we don't know exactly what it takes to finish it. Any longs or units she already shows must be subtracted from the numbers above.

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X - 2y = -3<br> 2x + y = -1
bezimeni [28]

Answer:

y = 1

x = -1

Step-by-step explanation:

x - 2y = -3, then x = 2y - 3

2x + y = -1

substitute for x:

2(2y - 3) + y = -1

4y - 6 + y = -1

5y = 5

y = 1

x = 2 - 3 = -1

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Answer:

15

Step-by-step explanation:

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Alana is having a party. She bought 3 rolls of streamers and 2 packages of balloons for $10.00. She realized she needed more sup
notsponge [240]
Streamers: 24 dollars Package of ballons: 6 dollars
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danny has a trianglular pyramid all triangles are conguent what is the surface area?​the height is 6in and the width is 5in
Gre4nikov [31]

Answer: The answer is 60 square inches.

Step-by-step explanation:  Given that Danny has a triangular pyramid where all the four triangles are congruent. The height and base of one triangle are 6 inches and 5 inches respectively. We are to find the surface area of the pyramid.

The area of one triangle is given by

A=\dfrac{1}{2}\times\textup{base}\times\textup{height}=\dfrac{1}{2}\times 5\times 6=15~\textup{sq. inches}.

Since the pyramid consists of four congruent triangles, so the surface area of the pyramid will be

S=4\times A=4\times 15=60~\textup{sq. inches}.

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Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t
Elenna [48]

Answer:

a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53  is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

a)

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

so

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

N^2 - 1000N + 50000 = 0

N = 1000 ± √(-1000)² - 4(1)(50000)) / 2(1)

N = 947.213 OR 52.786

approximately

N = 947 OR 53

Therefore Equilibrium point : [ 947, 53 ]

b)

g(N) = 2( 1 - N/1000)N - 100

= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) =  2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

now AT 53

g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53  is unstable equilibrium

The capacity k=1000

If the population is less than 53 then the population will become extinct but since the capacity is equal to 1000 then the population will not go extinct.

6 0
4 years ago
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