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Nady [450]
2 years ago
11

Abby uses base 10 blocks to show 1,109. She has no thousands cubes and only 9 flats, as shown. Draw longs and units on the chart

to finish Abby's model.
Mathematics
1 answer:
Vinvika [58]2 years ago
4 0

Answer:

  20 longs, 9 units more than the 9 flats

Step-by-step explanation:

If Abby has 9 flats, she has 900 blocks of the 1109 she needs. The remaining 209 can be represented by ...

  20 longs

  9 units

_____

<em>Comment on the question</em>

We cannot see the model Abby has put together so far, so we don't know exactly what it takes to finish it. Any longs or units she already shows must be subtracted from the numbers above.

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Shannon and Kelly spent $135 on gift certificates for their friends during the holidays. If this amount is 5/7 their total spend
Katena32 [7]

Answer:

$189

Step-by-step explanation:

Let their total amount of spending money be x

given that $135 they spent is 5/7 of their total spending money,

mathematically:

135 = (5/7) x     (multiply both sides by 7)

135 (7) = 5x

945 = 5x

5x = 945  (divide both sides by 5)

x = 945 / 5

x = 189

4 0
3 years ago
Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.
elena-s [515]

Answer:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64  

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

\theta=3.7\\\\and\\\\\theta=5.7

So, it's useful to solve the equation too, in order to verify the result:

-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}

Taking the inverse sine of both sides:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

\theta\approx 3.785\\\\\theta \approx 5.64

8 0
3 years ago
If your weight is 150 pounds and your mass is 15.3 kilograms, what would those values be if you were on the moon? The gravitatio
natulia [17]
Weight = mass * g  where g = gravitational force

so a weight of 150 pounds would be 150 / 6 = 25  on the moon.
The mass would be the same as on earth.
3 0
3 years ago
Need help ASAP now plz now z now now now
Viktor [21]
Root root 20^2 - 4^2
X = 2
6 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
wel

Answer:

z=\frac{15\sqrt{3}}{2}

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

tan(60)=\frac{y}{a}

now, we can solve for y

y=atan(60)

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

tan(30)=\frac{y}{15-a}

now, we can solve for y

y=(15-a)tan(30)

now, we can set them equal

and then we can solve for a

atan(60)=(15-a)tan(30)

\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3

4\sqrt{3}a=15\sqrt{3}

a=\frac{15}{4}

now, we can find b

b=15-\frac{15}{4}

b=\frac{45}{4}

now, we can use trig formula

cos(30)=\frac{b}{z}

now, we can find z

z=\frac{\frac{45}{4}}{cos(30)}

we can simplify it

and we get

z=\frac{15\sqrt{3}}{2}


4 0
3 years ago
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