Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)

The values of the cummulative distribution function of the standard Normal random variable, lets denote it
are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600

Hence, the proportion of scores reported as 1600 is 0.0032.
Answer:a
Step-by-step explanation:did
Answer:
![P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}](https://tex.z-dn.net/?f=P%28C%3D1%7CT%3D1%29%3Dq%28%5Csum_%7Bi%3D15%7D%5E%7B20%7D%5Cbinom%7B20%7D%7Bi%7D%20p%5Ei%281-p%29%5E%7B20-i%7D%29%28%20%5Csum_%7Bi%3D15%7D%5E%7B20%7D%5Cbinom%7B20%7D%7Bi%7D%5Bqp%5Ei%281-p%29%5E%7B20-i%7D%20%2B%20%281-q%29p%5E%7B20-i%7D%281-p%29%5Ei%5D%29%5E%7B-1%7D)
Step-by-step explanation:
Hi!
Lets define:
C = 1 if candidate is qualified
C = 0 if candidate is not qualified
A = 1 correct answer
A = 0 wrong answer
T = 1 test passed
T = 0 test failed
We know that:

The test consist of 20 questions. The answers are indpendent, then the number of correct answers X has a binomial distribution (conditional on the candidate qualification):

The probability of at least 15 (P(T=1))correct answers is:

We need to calculate the conditional probabiliy P(C=1 |T=1). We use Bayes theorem:

![P(T=1)=q\sum_{i=15}^{20}f_1(i) + (1-q)\sum_{i=15}^{20}f_0(i)\\P(T=1)=\sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i)]](https://tex.z-dn.net/?f=P%28T%3D1%29%3Dq%5Csum_%7Bi%3D15%7D%5E%7B20%7Df_1%28i%29%20%2B%20%281-q%29%5Csum_%7Bi%3D15%7D%5E%7B20%7Df_0%28i%29%5C%5CP%28T%3D1%29%3D%5Csum_%7Bi%3D15%7D%5E%7B20%7D%5Cbinom%7B20%7D%7Bi%7D%5Bqp%5Ei%281-p%29%5E%7B20-i%7D%20%2B%20%281-q%29p%5E%7B20-i%7D%281-p%29%5Ei%29%5D)
![P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}](https://tex.z-dn.net/?f=P%28C%3D1%7CT%3D1%29%3Dq%28%5Csum_%7Bi%3D15%7D%5E%7B20%7D%5Cbinom%7B20%7D%7Bi%7D%20p%5Ei%281-p%29%5E%7B20-i%7D%29%28%20%5Csum_%7Bi%3D15%7D%5E%7B20%7D%5Cbinom%7B20%7D%7Bi%7D%5Bqp%5Ei%281-p%29%5E%7B20-i%7D%20%2B%20%281-q%29p%5E%7B20-i%7D%281-p%29%5Ei%5D%29%5E%7B-1%7D)
The function that models the distance D from a point on the line y = 9 x - 8 to the point (0,0) (as a function of x) is y = 9x
Given the equation of a line in standard form as y = 9x - 8
Get the slope of the line
mx = 9x
m = 9
Since the line passes through the origin (0, 0), substitute the slope and the point in the point-slope form of the equation as shown below:


Hence the function that models the distance D from a point on the line y = 9 x - 8 to the point (0,0) (as a function of x) is y = 9x
Learn more here: brainly.com/question/15816805
Answer:
-20%
My brain is weird on how i figure it out but I divided 48 by 60 and got .80 so i just got the other whole to make it 1 so it is 20%. This is not the correct way to do this but this is how i got my answer.