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xenn [34]
3 years ago
5

The intersection of two planes is _____ a line. Always Sometimes Never

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0
The intersection of two planes is always a line
skad [1K]3 years ago
3 0

Answer:

The answer is Somtimes

Step-by-step explanation:

When you have two planes whose intersection is not the empty set, you have two posibilites:

- The two planes are the same. In this case you don't have a line as the intersection of them, but it is again a plane.

-The two plane s are not the same .    Then the intersection must be a line by an incidence axiom.

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What value in Vertex Form moves the graph up?
Leno4ka [110]
Changing from negative to positive
6 0
3 years ago
Express sin A,cos A and tan A as ratios
OverLord2011 [107]

Answer:

Part A) sin(A)=\frac{2\sqrt{42}}{23}

Part B) cos(A)=\frac{19}{23}

Part C) tan(A)=\frac{2\sqrt{42}}{19}

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

sin(A)=\frac{BC}{AB}

substitute the values

sin(A)=\frac{2\sqrt{42}}{23}

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

cos(A)=\frac{AC}{AB}

substitute the values

cos(A)=\frac{19}{23}

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

tan(A)=\frac{BC}{AC}

substitute the values

tan(A)=\frac{2\sqrt{42}}{19}

8 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary). (2,−3) and (0,−8)
saveliy_v [14]

Answer:

square root of 29

Step-by-step explanation:

use the distance formula and then plug the numbers in, i got the sqrt(29) after i did that

6 0
3 years ago
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
Find the value of $1000 deposited for 10 years in an account paying7% annual interest compounded yearly
Over [174]

Answer:

should be after 10 years , $1967.15

6 0
3 years ago
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