Find the equation of the line that is perpendicular to 3x + 2y = -2 and goes through the point (6,2)
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hey
let s note a and b the two numbers
we can write
(1) a = 2b - 2
(2) ab = 40
from (2) we can say for b different from 0 that
a = 40/b
replace it in (1)
40/b=2b-2
so
2(b-1)b = 40
b(b-1) = 20
5 is a trivial solution and as the product of the two solutions is -20 then the second solution is -4 therefore
<=> (b-5)(b+4) = 0
<=> b = 5 or b = -4
so we have
a= 40/b = 8 and b = 5
or
a = 40/b = -10 and b = -4
(8,5) and (-10.-4) are solutions
do not hesitate if you have any question
thanks