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umka21 [38]
2 years ago
9

Find the equation of the line that is perpendicular to 3x + 2y = -2 and goes through the point (6,2)

Mathematics
1 answer:
notka56 [123]2 years ago
4 0
Perpendicular lines have slopes that are inverse reciprocals of each other. That would give you the new slope in your equation. After that plug (6,2) into point slope form and solve to get your final equation.

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Pls answer and let me know if i can factor this r not
enyata [817]

Answer:

18r-4

Step-by-step explanation:

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6 0
2 years ago
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What are the factors of x^2-64
mel-nik [20]
Difference Of Two Squares
<span>a^2 - b^2 = a^2 - b^2 
</span><span>so
x^2-64
=x^2 - 8^2
= (x + 8)(x - 8)</span>
8 0
3 years ago
.chris p. bacon worked 44 hours last week and gets double time pay for overtime. his regular pay is $14 per hour. how much was h
masha68 [24]

The total paycheck for the week is of $672 as Chris bacon work for 44 hours last week, regular pay $14 per hour and double time pay for overtime.

As given,

Regular pay per hour = $14

Overtime work payment= 2 × ($14)

Total hours work done last week = 44hours

Let regular timing be 8 hours per day 5 days a week

Total regular working hours = 8 × 5

                                           = 40 hours

Over time = 44-40

                = 4 hours

Payment check = (40 × 14)+ (4 × 28)

                         = $672

Therefore, The total paycheck for the week is of $672 as Chris bacon work for 44 hours last week.

Learn more about work here

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8 0
2 years ago
Through (4,-4) ; perpendicular to 6y=x-12
BARSIC [14]

y = mx + b

m = slope and b = y-intercept


We can arrange 6y = x - 12 in the form of y = mx + b

                  6y = x - 12

                    y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

                  y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

                -4 = -6(4) + b

                 b = -4 + 6(4)

                 b = -4 + 24

                 b = 20

So the equation for the perpendicular line is y = -6x + 20

3 0
3 years ago
What are RQS and TQS?
yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

8 0
3 years ago
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