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3 years ago

Vertex, maximum height, and axis of symmetry

Mathematics

1 answer:

eduard3 years ago

6 0

Answer:

19 height

Step-by-step explanation:

sorry but thats all i know

hope it helps, have a nice day/night! :D

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Factor each polynomial. Look for a GCF first

weeeeeb [17]

Answer:

20. $x\left(x-6\right)\left(x+8\right)$

22. $2\left(x+1\right)\left(x+4\right)$

24. $5m\left(m-1\right)\left(m+7\right)$

Step-by-step explanation:

20. $x^3+2x^{2} -48x$

The GCF is x, so you group it out of the equation first.

$x(x^{2} +2x-48)$

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

$?+?=2\\?*?=-48$

The two numbers would be -6 and 8. You then differentiate the squares.

$x\left(x-6\right)\left(x+8\right)$

22. $2x^{2} +10x+8$

The GCF is 2, so you must group it out.

$2(x^{2} +5x+4)$

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

$?+?=5\\?*?=4$

The two numbers would be 1 and 4. Finally, differentiate the squares.

$2\left(x+1\right)\left(x+4\right)$

24. $5m^{3} +30m^2-35m$

The GCF is 5m, so you must group it out.

$5m(m^2+6m-7)$

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

$?+?=6\\?*?=-7$

The two numbers would be -1 and 7. Finally, differentiate the squares.

$5m\left(m-1\right)\left(m+7\right)$

7 0

2 years ago

What is the value of y when the value of x is 1 Car mileage for a hybrid car

Svetllana [295]

Answer: 60

Step-by-step explanation:

Just got the wrong answer to see what it was

8 0

3 years ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$