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Ahat [919]
3 years ago
10

A rectangular swimming pool is twice as long as it is wide. A small concrete sidewalk surrounds the pool and is a constant 2 fee

t wide. The total area of the pool and sidewalk is 160 square feet. Find the dimensions of the pool
Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

The dimensions of the pool are:

Width: 8.944 feet

Length: 17.888 feet

Step-by-step explanation:

From Geometry, the area of a rectangle (A), measured in square feet, is determined by the following equations:

A = w\cdot l (1)

Where:

w - Width, measured in feet.

l - Length, measured in feet.

If we know that w = x, l = 2\cdot x and A = 160\,ft^{2}, then we get the following second order polynomial:

2\cdot x^{2}-160 = 0 (1)

And we solve the expression for x:

2\cdot x^{2} = 160

x^{2} = 80

x = \sqrt{80}\,ft

x \approx 8.944\,ft

Then, the dimensions of the pool are, respectively:

w \approx 8.944\,ft and l \approx 17.888\,ft

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