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arsen [322]
3 years ago
7

saac and William, have found 11 quarters, 3 fifty-cent pieces, 36 dimes, 40 nickels, and 134 pennies. What is the experimental p

robability that the next coin they find is worth more than ten cents?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0
What you do is add up the coins in two piles
1. all the coins added up
2.coins that are more than 10 cents (or equal)
take number 2 and put that in the numerator (top spot on a fraction)
and take number 1  and put it on the denominator (bottom spot on a fraction)
then simplify it if needed.
50/224 is the raw data simplify it for the real answer
25/112 is the simplest you can do so there's your answer. hope this helped :)



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2 years ago
A total of 626 tickets were sold for the school play. They were either adult tickets or student tickets. There were 74 fewer stu
Sholpan [36]

Answer:

351 adults and 275 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 626 tickets were purchased, then s+a=626.

We also know that 74 fewer student tickets then adult tickets. So s+76=a, the number of student tickets plus 76 will be the number of adult tickets.

We will solve by substituting one equation into the other. We substitute a=76+s into s+a=626. Simplify and isolate the variable a.

s+a=626

s+76+s=626

2s+76=626

2s+76-76=626-76

2s=550

s=275

This means that 275 students attended and 351 adults attended since 275+351=626.


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4 years ago
Assume that the one-way commute time of an UoU student from his house to school is a normally distributed random variable which
Marizza181 [45]

Answer:

n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16

So the answer for this case would be n=16 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=10 represent the sample standard deviation

n represent the sample size  

ME=5 represent the margin of error

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (2)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (3)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.96, replacing into formula (3) we got:

n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16

So the answer for this case would be n=16 rounded up to the nearest integer

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