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Bond [772]
4 years ago
12

Alison is going camping and needs to get a tarp to cover the top of her tent. She has the following diagram of her tent. How lar

ge a tarp does she need?
A) 80 ft2
B) 105 ft2
C) 160 ft2
D) 185 ft2

Mathematics
1 answer:
Strike441 [17]4 years ago
3 0

Answer:

A 80ft

Step-by-step explanation:

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A civil engineer is mapping the overhead clearance of his family’s property on a coordinate grid. The ground is represented by t
statuscvo [17]

The distance from the base of the tree to the tallest would be 14.21 cm

<h3>We have the following data points in this question</h3>

X1 = 8 feet

y1 = 16 feet

x2 = 11 feet

y2 = 9 feet

To proceed with the solution we have to

We have to solve for the shorter tree

\sqrt{(y2 -y1)^2 + (x2-x1)^2} \\\\= \sqrt{9-0^2 + 11-0^2}

<em>= </em>9² + 11²

= √81 +121

= 14.21

<h3>For the taller tree we would have</h3>

√8² + 16²

= √64 +256

= 17.89

Read more on distance here:

brainly.com/question/2854969

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7 0
2 years ago
Write the word form for 3,500.16
Varvara68 [4.7K]
Three thousand five hundred and sixteen hundredths.
6 0
3 years ago
Read 2 more answers
How do I simplify −9(3−4w)−8w
laiz [17]
Multiply out the bracket so
-27 + 36w - 8w
Then collect the terms so
-27 + 28w

Answer = - 27 + 28w
3 0
3 years ago
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Use the properties of exponents to identify which exponential function is equivalent to f(x)=x^5/6• x^11/6
Daniel [21]

Answer:9898

Step-by-step explanation:

bc 9+8=0-9

5 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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