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3 years ago

Please help asap!!!!

Mathematics

1 answer:

iren2701 [21]3 years ago

8 0

Answer:

Step-by-step explanation:

yeyeyeye

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On Monday 573 students went on a trip to the zoo. All 9 buses were filled and 6 students had to travel in cars. How many student

arsen [322]

Answer: There are 41 students on each buss. Hope this helps!!

Step-by-step explanation:

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3 years ago

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How many liters equal 105 cubic centimeters? 10.5 L 1.05 L 1050 L 0.105 L

seropon [69]

Hello!

1 cubic centimeter = 0.001 liter

105 cubic centimeters = 0.001 × 105

0.001 × 105 = 0.105

Answer ⇒ 0.105 L

Hope this helps! :)

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2 years ago

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In the first week of July a record 1120 people went to the local swimming pool in the second week 105 fewer people went to the p

Westkost [7]

Answer:

25%

Step-by-step explanation:

The number of people who went to the local swimming pool in the;

first week = 1120

second week ( 105 fewer people) = 1120 - 105 = 1015

third week (135 more people) = 1015 + 135 = 1150

fourth week (310 fewer people|) = 1150 - 310 = 840

The percent decrease in the number of people who went to the pool over these four weeks

= (1120 - 840)/1120 * 100%

= 280/1120 * 100%

= 1/4 * 100%

= 25%

It means that the number of people who went to the local swimming pool over the 4 weeks decreased by 25%

5 0

3 years ago

2. What is the slope of a line that is parallel to the line shown?

alexandr1967 [171]

Answer:

Step-by-step explanation:

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3 years ago

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What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$

Substituting,

$E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}$

Factoring out the n and one p from the above expression:

$E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}$

Representing k=x-1 in the above gives us:

$E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}$

This can then be written by the Binomial Formula as:

$E[ X ] = (np) (p +(1 - p))^{n -1 }= np.$

5 0

3 years ago