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Nastasia [14]
3 years ago
10

Please help asap!!!!

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

C

Step-by-step explanation:

yeyeyeye

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When both equations have the same slope, but not the same y-intercept, they'll be parallel to each other and no intersections means no solutions. When both equations have different slopes than regardless of the y-intercept they'll intersect for certain, therefore it has exactly one solution.

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How do u simplify 5x^2-8x-12 subracted from -4x^2+2x-8
Nady [450]

Answer:

- 9x² + 10x + 4

Step-by-step explanation:

Calculate the subtraction as

- 4x² + 2x - 8 - (5x² - 8x - 12 ) ← distribute parenthesis by - 1

= - 4x² + 2x - 8 - 5x² + 8x + 12 ← collect like terms

= - 9x² + 10x + 4

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3 years ago
A tank contains 15,000 L of brine with 24 kg of dissolved salt. Pure water enters the tank at a rate of 150 L/min. The solution
Mashutka [201]

Answer:

Step-by-step explanation:

Let y(t) be the amount of salt in the tank after time t.

(A) Incoming rate = 0 (due to Pure water having no salt)

(B) Mixed solution comes out at 150 L/min. Initially the tank has 15,000 L of brine with 24 kg of salt.

concentration of salt at time t  = y(t) / 15000 kg/L

Outgoing rate = y(t)/15000 * 150 = y(t) / 100

(C) we know that,

\frac{dy}{dx} =(incoming\ rate) - (outgoing\ rate)

\frac{dy}{dx} =0-\frac{y(t)}{100} = \frac{-y(t)}{100}

Separate variable and integrate

\int {\frac{dy}{y} } = - \int {\frac{1}{100} } \, dt

ln|y|=-\frac{1}{100}t + D

y=e^{D} e^{\frac{-t}{100} }

y= Ce^{\frac{-t}{100} }\  [C=e^{D} ]

At t= 0 , y(0) = 24 kg

24=C\ e^{0}

C= 24

(D) Therefore, the amount of salt in the tank after time t :

y(t)=24e^{\frac{-t}{100} }\  kg

6 0
4 years ago
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