Question

Write an equation of the line passing through the given points.(1.-8) and (-2.10)y=?​

Answer 1

Answer:

The equation of line is $y=-6x-2$

Step-by-step explanation:

Given:

A line with two points on it are (1, -8) and (-2, 10)

Now, slope of a line passing through two points $(x_1,y_1)\ and\ (x_2,y_2)$ is given as:

$m=\frac{y_2-y_1}{x_2-x_1}$

Plug in $x_1=1,x_2=-2,y_1=-8,y_2=10$ in the above and solve for 'm'. This gives,

$m=\frac{10-(-8)}{-2-1}\\\\m=\frac{10+8}{-3}\\\\m=\frac{18}{-3}=-6$

Now, the equation of a line with slope 'm' and a point on it as $(x_1,y_1)$ is given as:

$y-y_1=m(x-x_1)$

Plug in -6 for 'm',$x_1=1\ and\ y_1=-8$. This gives,

$y-(-8)=-6(x-1)\\y+8=-6x+6\\y=-6x+6-8\\y=-6x-2$

Therefore, the equation of a line passing through the given points (1, -8) and (-2, 10) is $y=-6x-2$