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serg [7]
3 years ago
11

How many diagonals can be drawn from one vertex of a hexagon

Mathematics
2 answers:
Dmitrij [34]3 years ago
5 0
Three diagonals can be drawn in a hexagon mmyyy dude.
Zarrin [17]3 years ago
5 0
The hexagon has 6 vertices with 3 diagonals which gives you 18 divided by 2 = 9 diagonals
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If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7).
eimsori [14]
<h3>Answer:   -13</h3>

=======================================

Explanation:

g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)

g(1) = -4 means we have the point (1,-4)

Find the slope of the line through the two points (-3,2) and (1,-4)

m = (y2-y1)/(x2-x1)

m = (-4-2)/(1-(-3))

m = (-4-2)/(1+3)

m = -6/4

m = -3/2

m = -1.5

The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5

Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation:  2 = -1.5*(-3) + b

Let's solve for b

2 = -1.5*(-3)+b

2 = 4.5 + b

2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides

-2.5 = b

b = -2.5

Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5

The last step is to plug in x = 7 and compute

g(x) = -1.5*x - 2.5

g(7) = -1.5*7 - 2.5

g(7) = -10.5 - 2.5

g(7) = -13

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Answer:

Is it 1,512?

Step-by-step explanation:

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