Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
12,345 tablets may be prepared from 1 kg of aspirin.
Step-by-step explanation:
The problem states that low-strength children’s/adult chewable aspirin tablets contains 81 mg of aspirin per tablet. And asks how many tablets may be prepared from 1 kg of aspirin.
Since the problem measures the weight of a tablet in kg, the first step is the conversion of 81mg to kg.
Each kg has 1,000,000mg. So
1kg - 1,000,000mg
xkg - 81mg.
1,000,000x = 81

x = 0.000081kg
Each tablet generally contains 0.000081kg of aspirin. How many such tablets may be prepared from 1 kg of aspirin?
1 tablet - 0.000081kg
x tablets - 1kg
0.000081x = 1

x = 12,345 tablets
12,345 tablets may be prepared from 1 kg of aspirin.
The given function is

The general form of the cosine function is

a is the amplitude
2pi/b is the period
c is the phase shift
d is the vertical shift
By comparing the two functions
a = 4
b = pi
c = 0
d = 1
Then its period is

The equation of the midline is

Since the maximum is at the greatest value of cos, which is 1, then

Since the minimum is at the smallest value of cos, which is -1, then

Then substitute them in the equation of the midline

The answers are:
Period = 2
Equation of the midline is y = 1
Maximum = 5
Minimum = -3
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
#SPJ1
Answer:
Step-by-step explanation: dont work sorry