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Ira Lisetskai [31]
3 years ago
14

Fifteen minutes past eight in the evening on a 24 hour clock​

Mathematics
1 answer:
anastassius [24]3 years ago
4 0

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

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What is y - 8 = -1/2 (x + 4) in standard form (8th grade math)
Natalija [7]
Y-8=-1/2x + (-2)
  +8               +8
y=-1/2x +6
I just used a 2 step equation for it. I first used Distributive Property. Then Subtracted 8 from each side
7 0
3 years ago
to clean the fish tank 3/4 cups of disinfectant is needed for every two gallons of water how many cups of disinfectant are neede
choli [55]

Answer:

7 1/2 cups

Step-by-step explanation:

20 gallons is ten times 2 gallons.

Ten times the amount of water will require ten times the disinfectant (we assume).

... 10 × 3/4 cup = 30/4 cups = 7 1/2 cups

8 0
3 years ago
A patient requires a 30% decrease in the dosage of his meds. His current dose is 340 mg. What will his dosage be after the decre
Nookie1986 [14]

Answer:

238 mg

Step-by-step explanation:

340 x 0.30 = 102

340 - 102 = 238

4 0
3 years ago
The base of a triangle exceeds the height by 7 centimeters . If the area is 114 square centimeters, find the length of the base
Ganezh [65]

Answer:

base length = 19 cm  ,  height = 12 cm

Step-by-step explanation:

Area formula  :  A =  (1/2)*b*h

b = h + 7 cm

A = 114 sq. cm

114  =  (1/2) * (h + 7) *h

228 = hh + 7h

hh + 7h - 228 = 0

h = -7/2   +  root( 49 - 4*(-228)) /2

h = -7/2 + 31/2

h = 24/2 = 12 cm

base = 12 cm + 7 cm = 19 cm

5 0
4 years ago
If tan a = 3/4 find the value of sin 3a
Effectus [21]
T=-1

sinA=sin(π/2-3A), A=2nπ+π/2-3A, 4A=2nπ+π/2, A=nπ/2+π/8 where n is an integer.

Also, π-A=2nπ+π/2-3A, 2A=2nπ-π/2, A=nπ-π/4.

The hard way:

cos3A=cos(2A+A)=cos(2A)cosA-sin(2A)sinA.

Let s=sinA and c=cosA, then s²+c²=1.

cos3A=(2c²-1)c-2c(1-c²)=c(4c²-3).

s=c(4c²-3) is the original equation.

Let t=tanA=s/c, then c²=1/(1+t²).

t=4c²-3=4/(1+t²)-3=(4-3-3t²)/(1+t²)=(1-3t²)/(1+t²).

So t+t³=1-3t², t³+3t²+t-1=0=(t+1)(t²+2t-1).

So t=-1 is a solution.

t²+2t-1=0 is a solution, t²+2t+1-1-1=0=(t+1)²-2, so t=-1+√2 and t=-1-√2 are solutions.

Therefore tanA=-1, -1+√2, -1-√2 are the three solutions from which:

A=-π/4, π/8, -3π/8 radians and these values +2πn where n is an integer.

Replacing π by 180° converts the solutions to degrees.

3 0
3 years ago
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