All categories

3 years ago

Please help . I’ll mark you as brainliest if correct!!!!!!

Mathematics

2 answers:

STatiana [176]3 years ago

7 0

Answer:

3 are mushed

Step-by-step explanation:

You have 12 tomatoes

All but 9 get mushed

Total tomatoes = mushed + non mushed

12 = mushed +9

Subtract 9 from each side

12-9 = mushed+9-9

12-9 = mushed

3 = mushed

Dima020 [189]3 years ago

7 0

Answer:9

Step-by-step explanation:You just have to pay attention to the question and realize that it says that all the tomatos got ruined except 9

You might be interested in

I know the answer, I'm just confused on what to put for explore, plan, solve, and examine!

mestny [16]

Answer:

Explore - ??? (What are you suppose to put for that (Add comment))

Plan - First week - 53 Second week - 62

Solve - 53 + 62 = 115

Examine - (Use a graph to see the rise?)

Step-by-step explanation:

5 0

3 years ago

Write and solve a system of equations made up of Aiden's and Natalie's lines of best fit that they can use

dezoksy [38]

The catapult arm length for their tennis balls to cover the same distance is 32.3 feet.

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Given the equations:

Aiden: y = 2.3x + 160.7

Natalie: y = 3.6x + 202.6

For their tennis balls to cover the same distance:

2.3x + 160.7 = 3.6x + 202.6

1.3x = -41.9

x = -32.3

The catapult arm length for their tennis balls to cover the same distance is 32.3 feet.

Find out more on linear equation at: brainly.com/question/14323743

7 0

3 years ago

P (D) = .42, P (E) = .27, and P (D ∩ E) = .15 P (D U E)

Paul [167]

We know that $P(D\cap E)=P(D)P(E)=\boxed{0.1134}$ .

And $P(D\cup E)=P(D)+P(E)-P(D\cap E)=\boxed{0.5766}$ .

Hope this helps.

6 0

3 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

3 years ago

I need help is it A B C or D

deff fn [24]

I would say c as the answer

8 0

3 years ago

Read 2 more answers