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icang [17]
3 years ago
6

a swimming pool is 60m long and 25m wide. it is filled with water to a depth of 7m. find the volume of water in the pool​

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

10500 m³

Step-by-step explanation:

60 × 25 × 7 = 10500 m³

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
Please answer correctly !!!!!! Will mark brainliest answer !!!!!!!!!!!!!!
AlekseyPX

Answer:

(up) by 6

left by 7

Step-by-step explanation:

7 0
3 years ago
The next model of a sports car will cost 4.7% less than the current model the current model cost 31000. How much will the price
natka813 [3]

Step-by-step explanation:

decrease value is 1353

value 31,647

7 0
2 years ago
I really need help on this please
Gala2k [10]

Answer:

When you simplify you get 5/6. Hence both x can be removed and when divided by the exponents you get x cannot be equal to zero. The Answer is the second.

Step-by-step explanation:

6 0
2 years ago
280 m
Marianna [84]

Answer: C. 1,183m

Step-by-step explanation:

6 0
2 years ago
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