Surface area = 12*9 + 2*12*10 + 2*9*10 = 528 in^2 Answer
(its only one 12*9 because it is open at the top)
Answer:
y = 2x-16
Step-by-step explanation:
To find a line when we know the slope and a point, we can use the point slope formula for a line
y-y1 = m(x-x1)
where the point is (x1,y1) and the slope is m. Substituting the known information in.
y--8 = 2 (x-4)
y+8 = 2(x-4)
We can manipulate this into slope intercept form by distributing the 2
y+8 = 2x-8
and subtracting 8 from each side
y+8-8 = 2x-8-8
y = 2x-16
The answer is 42/50 or 21/25
The problem is looking for the area of the trapezoid. To solve for the area of a trapezoid, we can cut them into different shapes like rectangle and triangles.
First, we draw altitudes at M and L to make a rectangle with length 22 ft and width 17 ft. We subtract 22 ft from 32 ft and divide it by 2 in order to get the base for each triangle.
(32-22)/2 = 5 ft.
Next, we find the area of the rectangle. A = LW = 22 ft x 17 ft = 374 ft^2.
Then we find the area of the triangle: A = 0.5BH = 0.5 x 5 ft x 17 ft = 42.5 ft^2
Total area = 374 ft^2 + 2(42.5 ft^2) = 459 ft^2.
The answer is D.