Answer:
(fog)(a) = a³ - 3a² + 4a - 2
= (a - 1)×(a² - 2a + 2)
Step-by-step explanation:
<u><em>Given</em></u> :
g(a) = a -1
f(a)= a³ +a
…………………………
(fog)(a) = f(g(a)))
= g(a)³ + g(a)
= (a - 1)³ + (a - 1)
= (a³ - 3a² + 3a - 1) + (a - 1)
= a³ - 3a² + 3a - 1 + a - 1
= a³ - 3a² + 3a + a - 1 - 1
= a³ - 3a² + 4a - 2
<u><em>Second method</em></u> :
(fog)(a) = f(g(a)))
= f(a - 1)
= (a - 1)³ + (a - 1)
= (a - 1)×[(a - 1)² + 1]
= (a - 1)×[a² - 2a + 1 + 1]
= (a - 1)×(a² - 2a + 2)
Answer:
0.667 ;
0.667 customers ;
0.0166708 hour ;
1.334 customers
Step-by-step explanation:
Given that:
Service time (μ) = 30 seconds ; 2 customers per minute ; 2 * 60 = 120 customers per hour
Arrival time, λ = 80 customers per hour
a.) percentage of time machine is busy (p) ; Utilization factor :
P = λ/ μ = 80 / 120 = 0.667
b.) average number of customers waiting in line Li = p² / 2(1-p)
= 0.667² / 2(1-0.667) = 0.667 customers
c) Average time customer spend in the system = Li/λ + 1/μ
= (0.667 / 80) + (1 / 120)
0.0083375 + 0.0083333
= 0.0166708 hour
= 0.0166708 * 60 = 1.00025 minutes
D) average number in the system ;
Li + p
= 0.667 + 0.667 = 1.334 customers
Answer:
600
Step-by-step explanation:
hope it helps :)
Answer:
Step-by-step explanation:
radius (r) = 4 cm
area of the circle
= π * r²
= 3.14 * 4 * 4
=50.24 cm²
hope it will help :)