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statuscvo [17]
3 years ago
15

How do you write  78. 63  as a fraction?

Mathematics
2 answers:
Crazy boy [7]3 years ago
7 0
78.63 written as a fraction is 7863/100 or 78 63/100.

I hope this helps!
ladessa [460]3 years ago
6 0
That would be 78 63/100. 




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Michael has 567 pennies, Jorge has 464 pennies, and Jamie has 661 pennies. If the pennies are shared equally by the 3 boys and 3
GuDViN [60]

Answer:

Everybody, including the three boys, will get 47 pennies.

Step-by-step explanation:

First, you add the number of pennies each of the boys has, 567+464+661 = 1,692. Then you take the 1,692 and divide it by 36 to get 47. You divide by 36 because the pennies are getting shared by the 3 boys and 33 classmates, which comes out to be 36 classmates in total.

3 0
4 years ago
Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production
Lena [83]

The question supplied is incomplete :

The x parameters aren't given ; "Units with weights less than or greater than ounces will be classified as defects"

Assume the unit weights Given are ;

Units with weights less than 10.8 or greater than 11.2 ounces will be classified as defects

Just follow the procedure in the solution for any value of unit weight interval given.

Answer:

0.3173

Step-by-step explanation:

Mean weight, m = 11 ounces

Standard deviation, s = 0.2 ounces

Find the Zscore for each unit weight :

Z = (x - mean) / standard deviation

P(x < 10.8) :

Z = (10.8 - 11) / 0.2 = - 1

P(Z < - 1) = 0.15866

P(x > 11.2) :

Z = (11.2 - 11) / 0.2 = 1

P(Z > 1) = 0.84134

P(x < 11.2) - P(x < 10.8) = 1 - (P(Z < 1) - P(Z < - 1)) = 1 - 1 - (0.84134 - 0.15866) = 1 - 0.68268 = 0.31732

Hence, Probability of a defect is 0.3173

7 0
3 years ago
Po is an oncologist with seven patients in their care. the probability that a patient will survive five years after being diagno
alekssr [168]

Answer:

0.0923 = 9.23% probability that four of the patients are still alive after five years.

Step-by-step explanation:

For each patient, there are only two possible outcomes. Either they are still alive after five years, or they are not. The probability of a patient being alive is independent of any other patient, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Po is an oncologist with seven patients in their care.

This means that n = 7

The probability that a patient will survive five years after being diagnosed with stage three breast cancer is 0.82.

This means that p = 0.82

What is the probability that four of the patients are still alive after five years?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{7,4}.(0.82)^{4}.(0.18)^{3} = 0.0923

0.0923 = 9.23% probability that four of the patients are still alive after five years.

5 0
3 years ago
Mateo has been studying after school while preparing for a test retake. His work paid off ! His score on the retake was a 94. Th
Feliz [49]

Answer:

28%

Step-by-step explanation:

We know that 100 percent is total. Mateo first scored 68/100, then a retake got his score up to 94/100.

First, subtract the two numbers

94 - 68 = 26

Put 26 over 94 to make this 26/94

Divide to get 0.28 (simplified and rounded)

So the increase was 28%

7 0
3 years ago
Read 2 more answers
HELPPPPPP ILL GIVE BRAINLEST !!!!! PLEASE
Gre4nikov [31]
113
42
13

Hope this helps have a good day
6 0
3 years ago
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