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kow [346]
3 years ago
13

An airplane flies due North at 100mph through a 30mph cross wind blowing from S80E. Determine the resultant velocity and directi

on of the airplane
Mathematics
1 answer:
stealth61 [152]3 years ago
3 0

Answer:

velocity of the airiplaine is 104 m/s ( 73 degrees N of W)

Step-by-step explanation:

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Please help with the screenshot
oksian1 [2.3K]

Answer:

x = 10.73

Step-by-step explanation:

\sin(59)  =  \frac{9.2}{x}

x =  \frac{9.2}{ \sin(59) }  = 10.73

7 0
3 years ago
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Which option do I choose?
garik1379 [7]

Answer:

  Does exist -- It only exists when the determinant does not equal zero.

Step-by-step explanation:

The inverse of a matrix is the transpose of the cofactor matrix, divided by the determinant. If the determinant is zero, the result of the division is undefined and the inverse does not exist.

__

For this matrix, the determinant is (-2)(18) -(9)(4) = -72. The inverse exists.

5 0
4 years ago
Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form?
fomenos
1, when you factor you get 6x(x^2-1)+4(x^2-1)=(6x+4)(x-1)(x+1)
7 0
3 years ago
Can someone help me with this question ?
kramer
The correct answer is 8 feet tall
3 0
3 years ago
Read 2 more answers
The position of a model train, in feet along a railroad track, is given by
miv72 [106K]

Answer:

Part a) The speed is 2.5\frac{ft}{sec}

Part b) After 4 seconds the trains is 24 ft along the track

Part c) t=6\ sec

Step-by-step explanation:

we have

s(t)=2.5t+14

This is the equation of a line in slope intercept form

where

s(t) is the position of a model train in feet

t is the time in seconds

Part a) How fast is the train moving?

The speed of the train is equal to the slope of the linear equation so

The slope m is equal to

m=2.5\frac{ft}{sec}

therefore

The speed is 2.5\frac{ft}{sec}

Part b) Where is the train after 4 seconds?

For t=4 sec

substitute the value of t in the equation and solve for s

s(4)=2.5(4)+14=24\ ft

therefore

After 4 seconds the trains is 24 ft along the track

Part c) When will the train be 29 feet along the track?

For s(t)=29 ft

Substitute the value of s(t) in the equation and solve for t

29=2.5t+14

subtract 14 both sides

29-14=2.5t

15=2.5t

Divide by 2.5 both sides

6=t

rewrite

t=6\ sec

3 0
3 years ago
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