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OleMash [197]
3 years ago
6

Drag the labels to the correct locations on the expanded binomial.

Mathematics
1 answer:
Tom [10]3 years ago
6 0

The expanded binomial is 2x^3+3y^2=7                                                                                              

<u>Step-by-step explanation</u>:

  • The binomial is not shown in correct expansion. It is written in the wrong format. There is a general format for the binomial expansion.
  • The first term should have the highest power. So 2x power 3 will come first. The second term will have power lesser than the first term.
  • So in the second term, 3y^2 will be placed. After that, the equal to = operator will be placed. Finally, the value of the expression will be placed.
  • So the expanded correct form is 2x^3+3y^2=7                                              

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The graph of the function f(x) = (x – 4)(x + 1) is shown below. On a coordinate plane, a parabola opens up. It goes through (neg
DanielleElmas [232]

Answer:

The function is decreasing for all real values of x where x < 1.5.

Step-by-step explanation:

we have

f(x)=(x-4)(x+1)

f(x)=x^2+x-4x-4

f(x)=x^2-3x-4

This is a vertical parabola open upward

The vertex is a minimum

The vertex is the point (1.5,-6.25)

we know that

The function is decreasing in the interval ----> (-∞,1.5)  x < 1.5

That means----> the function is decreasing for all real values of x less than 1.5

The function is increasing in the interval ----> (1.5,∞)  x> 1.5

That means----> the function is increasing for all real values of x greater than 1.5

see the attached figure to better understand the problem

therefore

The statement that is true is

The function is decreasing for all real values of x where x < 1.5.

5 0
4 years ago
Read 2 more answers
Sydney has a bag of stuffed animals containing, 1 elephant, 4 bears, 3 cats, and 2 dogs. If she randomly selects 1 stuffed anima
torisob [31]

Answer:

2/15

Step-by-step explanation:

Step one:

given data

sample space

1 elephant,

4 bears,

3 cats, and

2 dogs.

sample size= 1+4+3+2= 10

Required:

By selecting without replacement, the probability that she chooses a bear both times

Step two:

the first event= Pr(bear)= 4/10= 2/5

the second event, the sample size is now 9 and the number of bears is now 3

Pr(bear)= 3/9= 1/3

Hence, the probability that she chooses a bear both times

= 2/5*1/3

=2/15

3 0
4 years ago
This year the fifth grade collected 216 fewer plastic containers than the fourth grade.How many plastic containers did the fifth
kap26 [50]

Let number of plastic containers collected by fourth grade= x

Then number of plastic containers collected by fifth grade students=x-216

OR

If number of plastic container collected by fifth grade is y

then number of plastic container collected by fourth grade=y+216

So, we can write it as follows

⇒ number of plastic containers collected by fourth grade= number of plastic containers collected by fifth grade +216



7 0
3 years ago
$\triangle abc$ and $\triangle dbc$ share $bc$. $ab = 5\ \text{cm}$, $ac = 12\ \text{cm}$, $dc = 8\ \text{cm}$, and $bd = 20\ \t
Ratling [72]
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5+x>12
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x>7
x>12
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<span>The least possible integral is 13.

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6 0
4 years ago
M(d)=-0.123x^2+148.83x-21.07<br> When will it reach maximum height of 45000 feet
Setler [38]

Answer: time to reach maximum height = 605

Step-by-step explanation:

The expression that relates height with time is

M(d)=-0.123x^2+148.83x-21.07

Where time = x

d = height

The expression is a quadratic equation. If height of the object is plotted against time, the resulting graph is a parabola whose vertex is equal to the maximum height attained by the object. The time, x corresponding to the vertex is the time for it to reach maximum height.

To find x,

x = -b/2a

Where a= 0.123

b = 148.83

x = - 148.83 / -2 × -0.123

x = -148.83 / -0.246

= 605

Substituting x = 605 in the equation,

M(d)=-0.123x^2+148.83x-21.07

d = -0.123 × 605^2 + 148.83×605

= - 45021.075+ 90042.15

= 45020.4

Approximately 45000 feet

6 0
3 years ago
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