PLEASE HELP!!!

Find the y-intercept of the line. If needed use "/" for a fraction. b= <br><br>y=10+4x

11111nata11111 [884]

Y-intercept(b)= 10

equation wasnt written in the correct order so b is 10

7 0

1 year ago

PLEASE!!!

ANEK [815]

9514 1404 393

Answer:

30m +50 = 20m +100
m = 5
yes. symmetric property of equality.

Step-by-step explanation:

1. The expression for c in the first equation is (30m+50). Substituting that for c in the equation ...

c = 20m +100

gives you ...

30m +50 = 20m +100

__

2. Adding -50-20m to both sides gives ...

10m = 50

m = 5 . . . . . . . divide by 10

__

3. Doing the substitution in reverse, you would substitute (20m+100) for c in the equation ...

c = 30m +50

to get ...

20m +100 = 30m +50

This is the equation of part 1 with the expressions swapped to the other side of the equal sign. The symmetric property of equality tells you that changing sides of the equal sign does not change the value of the variable(s).

You get the same solution.

3 0

3 years ago

Which equation describes how the parent function y=x^3, is vertically streched by a factor of 4

Murljashka [212]

Answer:

$y=4x^{3}$

Step-by-step explanation:

It is known that,

<em>'Vertical stretch, stretches the function up and down towards the y-axis'.</em>

The general form of vertical stretch is given by 'kf(x)', where k>1 is the factor by which function is stretched.

As, we have the function $y=x^{3}$ which is stretched by a factor of 4.

Thus, the new function will be $y=4x^{3}$ .

Hence, the equation for the vertical stretch is $y=4x^{3}$ .

8 0

3 years ago

A recent study of 26 city residents showed that the time they had lived at their present address has a mean of 10.3 years with t

svetlana [45]

Answer:

The 95% confidence interval is $9.15< \mu < 11.45$

Step-by-step explanation:

From the question we are told that

The sample size is n = 26

The mean is $\= x = 10.3$

The standard deviation is $s = 3$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{3}{\sqrt{26} }$

=> $E = 1.1532$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $10.3 -1.1532 < \mu < 10.3 + 1.1532$

=> $9.15< \mu < 11.45$

7 0

3 years ago

Kckkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

bogdanovich [222]

Answer:

um OK

Step-by-step explanation:

f

8 0

3 years ago