Can 100+25 sqrt(2) be simplified?
1 answer:
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Answer:
Approximately 17.88x or
Step-by-step explanation:
Use pythagorean formula. In a rhombus the diagonals bisect each other and they are perpendicular, so you could have a right triangle with legs of 2x and 4x, the hypoteneuse would then be which is approximately 4.47x. In a rhombus all 4 sides are the same, so multiply that by 4 and you get the perimeter. 4(4.47x) = 17.88x or if you simplify the radical instead it's
9514 1404 393
Answer:
A, C
Step-by-step explanation:
The attached graph shows which lines go through the given point. They are ...
y = 1/2x -1 . . . . 1st selection
y = -1/6x +3 . . . 3rd selection
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The equations can be found algebraically by substituting the given point in the equation and seeing if the result is a true statement.
a) 2 = (1/2)(6) -1 = 3 -1 . . . true
b) 2 = -3(6) . . . . false
c) 2 = -1/6(6) +3 = -1 +3 . . . true
d) 2 = 2/3(6) -1 = 4 -1 . . . . false
e) 2 = 4(6) -2 = 24 -2 . . . . false
f) 2 = -3/2(6) +6 = -9 +6 . . . . false
