Option B. From the parallelogram PQRS the value of y is given to be 30
<h3>How to solve for the value of y from the parallelogram</h3>
In order to get the value of y we have to use the formula
2y + 120 = 80
where the value 120 is the angle that is stated as 120 from the question
2y = 180 - 120
2y = 60
y = 60 / 2
y = 30
Hence the value of y = 30
We can go ahead to get the value of x as well
3x + 120 = 180
take the like terms
3x = 180 - 120
3x = 60
divide through by 3 to get x
60 / 3 = x
20 = x
Read more on parallelograms here: brainly.com/question/24056495
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Answer:
The correct answer is option <em>B. AA</em>
<em></em>
Step-by-step explanation:
Given two triangle:
and
.
The dimensions given in
are:

We know that the sum of three angles in a triangle is equal to
.

The dimensions given in
are:

We know that the sum of three angles in a triangle is equal to
.

Now, if we compare the angles of the two triangles:

So, by AA postulate (i.e. Angle - Angle) postulate, the two triangles are similar.
by <em>AA theorem.</em>
<em>So, correct answer is option B. AA </em>
1 cup: 8 oz
1 pint: 2 cups
2 pints: 1 quart
4 quarts: 1 gallon
by looking at this scale you will multiply the needed #s:
2 times 2 = 4 4 times 4 = 16 so there are 16 cups in a gallon
<span>2y = x + 3 then x = 2y - 3
5y = x - 7 then x = 5y + 7
so
</span>2y - 3 = 5y + 7
2y - 5y = 7 + 3
-3y = 10
y = -10/3
y = -3 1/3
<span>2y = x + 3
</span>2 (-10/3) = x + 3
-20/3 - 3 =x
-29/3 = x
-9 2/3 =x
or
x = -9 2/3
solutions: x = -9 2/3 and y = -3 1/3
We are given the functions:
<span>P (d) = 0.75 d --->
1</span>
<span>C (P) = 1.14 P --->
2</span>
The problem asks us to find for the final price after
discount and taxes applied; therefore we have to find the composite function of
the two given functions 1 and 2. To solve for composite function of the final
price of the dishwasher with the discount and taxes applied, all we have to do
is to plug in the value of P (d) with variable d into the equation of C (P).
That is:
C (P) = 1.14 (0.75 d)
C (P) = 0.855 d
or
<span>C [P (d)] = 0.855 d</span>