If we were to plot the points on a graph, we could draw a straight lint between them. The question wants us to find the length of this line. We could make a right triangle with this line as the hypotenuse, with an x length of 2(y2-y1) and a y length of 5 (y2-y1). From there we can find the hypotenuse with Pythagorean Theorem: c^2=a^2+b^2.
c^2=(2)^2+(5)^2
c^2=4+25
C^2=41
c=
Decimal approximation: 6.403
Hope this helps!
Answer:
SLOPE is m = −4/3
Step-by-step explanation:
-20.01
-20.02
-20.03
and so on
all the way to 20.99
Good evening Brian,
For this problem, let's look at what we're given. So we have a pool with a length that is 13 m (meters) longer than its width, and we're given the perimeter, or distance around the entire pool, which is 74 m.
We know that the pool has a rectangular shape and that the perimeter of a rectangle is <span>width + length + width + length ⇒ 2(W) + 2(L)</span>.
Given the information provided, we can rewrite the equation to fit this problem. Since we're told that the length is equal to 13 m + the width, so we can represent the length as W +13 m. We can now rewrite the perimeter equation to be:
2(w) + 2 (w + 13 m) ⇒ 2(w) + 2(w) + 2(13 m) ⇒ 4(w) + 26 m = 74 m.
We're down to one variable now so this should be easy. Subtract 26 m from both sides,
4(w) = 48 m
Now divide each side by 4 in order to find the width.
w = 12 m
-Hope this helps!
Answer: - 2.4x^2 - 1.5x - 11.4
Step-by-step explanation:
- 4.1x^2 + 0.9x - 9.81.7x^2 - 2.4x - 1.6 = - 2.4x^2 - 1.5x - 11.4
