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svet-max [94.6K]
3 years ago
9

Using partial quotients what is the answer to 4÷92

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0
Well, you could easily type that into a calculator, but the answer would be 0.04347826, but when you say it as an answer you say the answer up to the hundredths place, which would be 0.043. =)
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Rachel works at a bookstore. On Tuesday, she sold twice as many books as she did on Monday. On Wednesday, she sold 6 fewer books
natali 33 [55]
Let m = the amount books Rachel sold on Monday.
then t = the amount books Rachel sold on Tuesday.<span>
then w = </span><span>the amount books Rachel sold on Wednesday.

On Tuesday she sold twice as she did on Monday.
 t = m * 2

On Wednesday she sold 6 fewer books than she did on Tuesday
w = t - 6

Now for the fun.

t = m * 2
w = t - 6

Substitute t for real value

w = m * 2 - 6

Now solve for m.

w - 6 = m * 2 <-- Transpose the 6
(w-6)/2 = m <-- Transpose the 2.
m = (w-2)/2 < The Law of Reflexive Property of Equality</span>
3 0
3 years ago
Read 2 more answers
Write the following decimal number in its equivalent fraction form. Show all work for full credit.
Zigmanuir [339]
<span>Let x=0.8888... 

x=0.8888 Start with the given equation 

10x=8.8888 Multiply both sides by 10. The goal is to move the decimal point to the next repeating portion (which is just one spot to the right) 



 Now subtract the equation x=0.8888 from 10x=8.8888 to get 
10x-x=8.8888-0.8888 

9x=8 Combine like terms. Notice how the decimal portions cancel out. 

x=8/9 Divide both sides by 9 to isolate x 

So the answer is x=8/9 which means that 8/9=0.8888 (where the 8's repeat)</span>
 
8 0
3 years ago
What is the length of DE
Valentin [98]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
For each of the following shapes, state whether or not it has reflection symmetry. If it does , draw the lines of symmetry it.
Effectus [21]
You would have to draw a line across
5 0
2 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
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