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3 years ago

Suppose that the function fis defined on the interval (-2,2) as follows. find f(-1) f(0.5) f(1)

Mathematics

1 answer:

frosja888 [35]3 years ago

8 0

Answer:

Step-by-step explanation:

Hello,

-1 <= -1 < 0

so f(-1)=-1

0 <= 0.5 < 1

so f(0.5)=0

1 <= 1 < 2

so f(1)=1

Thank you.

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Answer:

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General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

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Definite Integrals
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Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

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Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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Suppose that the function fis defined on the interval (-2,2) as follows. ​find f(-1) f(0.5) f(1)

Suppose that the function fis defined on the interval (-2,2) as follows. find f(-1) f(0.5) f(1)