Answer:
Step-by-step explanation:


Volume = 
find partial derivatives using product rule

i.e.
Using maximum for partial derivatives, we equate first partial derivative to 0.
y=0 or x+y =6
x=0 or x+4y =12
Simplify to get y =2, x = 4
thus critical points are (4,2) (6,0) (0,3)
Of these D the II derivative test gives
D<0 only for (4,2)
Hence maximum volume is when x=4, y=2, z= 4/3
Max volume is = 4(2)(4/3) = 32/3
Answer:
Step-by-step explanation:
y=2x²-6x+3
y=2x+3
2x²-6x+3=2x+3
2x²-6x+3-2x-3=0
2x²-8x=0
2x(x-4)=0
x=0,4
y=0+3=3
and y=2(4)+3=11
so solutions are (0,3) and (4,11)