The answer will be 625j^4 k^4
(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3
= a^4b^9/2a^8b^4
=b^5/2a^4
so your answer is b^5/2a^4

- The name of the circle is <u>IJKL</u>
- The name of central Angle

- The name of the secant = <u>KL</u>
Circle :- It is a round figures, which has no end points.
Central angle :- It the angle ,which lie in the middle of the circle.
- Here, H is the mid point of the circle .So, Angle IHJ is the central angle.
Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .
- Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

- Semicircle = FGH and FIH
- Minor Arc :- FG or GH
- Major Arc :- FHG or GFH
Semicircle :- Semicircle is nothing but the half of the circle.
<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>
- FGH and FIH are acting as two semicircles which simulatineously forming one circle.
Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FG or GH are the minor arc of the given circle.
Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FHG or GFH is the major arc as it is larger than the semicircle of the given circle .
Answer: p-8
Step-by-step explanation:first thins problem is impossible without knowing the lifespan of a puma. But if you knew it oh let’s say it was 20 you would subtract the puma by 8.