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3 years ago

what is the surface area of a rectangular prism whose base is 5 inches by 6 inches and whose height is 5 inches?

Mathematics

1 answer:

Ugo [173]3 years ago

6 0

160 inches... I am 98% sure I am correct

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What is the area of this figure?

Elza [17]

The bottom square portion would be 10 x 10 = 100 square inches.

The area of the triangle would be 1/2 x base x height.

The base is 10 - 6 = 4 inches.

The height is 16 -10 = 6 inches.

Area = 1/2 x 4 x 6 = 12 square inches.

Total area = 100 + 12 = 112 square inches.

6 0

3 years ago

Read 2 more answers

What are the steps to solve (5xy^3)^2(xy)^4?

Alexeev081 [22]

Answer:

$25x^6y^{10}$

Step-by-step explanation:

$(5xy^3)^2(xy)^4\\\\5^2*x^2*(y^3)^2*x^4*y^4\\\\25*x^{2+4}*y^{3*2}*y^4\\\\25*x^6*y^6*y^4\\\\25x^6*y^{6+4}\\\\25x^6y^{10}$

Remember to use your exponent rules

3 0

2 years ago

Read 2 more answers

HELP ME PLEASE I'll give brainless.

Nikitich [7]

MLJ is congruent to POL( corresponding angles)
POL= 59

8 0

3 years ago

24 x1/3

hodyreva [135]

9514 1404 393

Answer:

Step-by-step explanation:

$24\times\dfrac{1}{3}=\dfrac{24}{3}= \dfrac{3\cdot8}{3}=\dfrac{3}{3}\cdot8 = 1\cdot8 = \boxed{8}$

Multiplying by 1/3 is the same as dividing by 3.

5 0

3 years ago

Which statements are true about the trigonometric ratios of this triangle

rosijanka [135]

Answer:

Options (1), (2), (3) and (4)

Step-by-step explanation:

By applying the sine and cosine rules in the given triangle,

sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

cos(30°) = $\frac{AC}{AB}$

= $\frac{11\sqrt{3} }{22}$

= $\frac{\sqrt{3}}{2}$

sin(30°) = $\frac{BC}{AB}$

= $\frac{11}{22}$

= $\frac{1}{2}$

cos(60°) = $\frac{BC}{AB}$

= $\frac{11}{22}$

= $\frac{1}{2}$

sin(60°) = = $\frac{AC}{AB}$

= $\frac{11\sqrt{3} }{22}$

= $\frac{\sqrt{3}}{2}$

Options (1), (2), (3) and (4) are the correct options.

3 0

2 years ago