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3 years ago

help asap pls!!!!!!!!!! Which equation can be used to determine the distance between the origin and (–2, –4)?

Mathematics

1 answer:

Semenov [28]3 years ago

8 0

We know that
the distance formula is
d=√[(y2-y1)²+(x2-x1)²]
point (0,0) and point <span>(–2, –4)
</span>d=√[(-4-0)²+(-2-0)²]---------> d=√[16+4]-------> d=√20
d=4.47 units

the answer is the option B
see the attached figure

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3 years ago

Wich of the following expressions are equivalent to - 2/3 ? select all that apply

MrRa [10]

Answer:

A, C and E

Step-by-step explanation:

Simplify each expression to lowest terms. Equivalent expressions will be any expressions which are equal after simplifying to lowest terms.

A. -1/9 * 6 = -6/9 = -2/3

B. -15/10 = -3/2

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3 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

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3 years ago

4. Which is an equation of a line that is parallel to<br> the graph of y = {x - 52

kifflom [539]

Answer:

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Step-by-step explanation:

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