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Nitella [24]
3 years ago
13

Given the arithmetic series 2 4 6...=420. find the first term a and the common difference d

Mathematics
1 answer:
Trava [24]3 years ago
7 0
First term is 2 and the common difference is the value by which it increases which is 2.
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Please Help! Geometry!
tresset_1 [31]

Step-by-step explanation:

At first we can find AC

then we can find m<A and m< C

or, m<C and then m< A

m<B is already given in the question so there is no need of finding it.

7 0
3 years ago
When multiplying decimals how do you determine where yo place the decimal in the answer?
Aneli [31]
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3 0
4 years ago
Plz help 2-7x-5x=-2-8x-5x
anyanavicka [17]

Answer:

x=-4

Step-by-step explanation:

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%2010%20%5Ctimes%2018%20%7Br%7D%5E%7B%20-%208%7D%20%20%3D%20%20-%202" id="TexFormula1" tit
grigory [225]

Answer:

1.107   =  r

Step-by-step explanation:

To solve this for r, do the following:

Add 10 to both sides, to isolate the r term on the left:  18r^(-8) = 8

Divide both sides by 18, to isolate r^(-8):   r^(-8) = 8/18

Invert both sides:  r^8 = 9/4

Take the natural log or both sides:

8 ln r = ln 9 - ln 4, or

8 ln r = 0.8109, so that ln r = 0.1014

to find r, raise e to the power ln r on the left and e to the power 0.1014 on the right:

  ln r           0.1014

e         =    e              =  1.107   =  r

3 0
4 years ago
What is the smallest 3-digit palindrome that is divisible by both 3 and 4?
kirill [66]

Answer:

252

Step-by-step explanation:

To be divisible by 3, it's digits have to add to a number that is a multiple of 3.

To be divisible by 4 its last 2 digits have to be divisible by 3.

So let's start with 1x1 which won't work because 1x1 is odd. so let's go to 2x2 and see what happens.

212 that's divisible by 4 but not 3

222 divisible by 3 but not 4

232 divisible by 4 but not 3

242 not divisible by either one.

252 I think this might be your answer

The digits add up to 9 which is a multiple of 3 and the last 2 digits are divisible by 4

4 0
3 years ago
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