Can y’all try to solve some of these for me?

Mathematics

1 answer:

RoseWind [281]3 years ago

7 0

Answer:

The 3rd problem on mondays answer is 2:1

The 4th problem on monday answer is it is not long enough he needs to make it 4 inches longer.

The 5th problem on monday is 41

The 6th problem on monday is 13,12,11

Can't read the whole problem for the 7th question on monday

the 8th problem on monday is 55 and 8/15

That is the answers for monday hope this helps

Step-by-step explanation:

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Point C is located 8 inches from point A and 6 inches from point B. Points A and B are 2 inches apart.

marshall27 [118]

Answer:

Step-by-step explanation:

4 0

3 years ago

Use these functions to answer the questions.

Elenna [48]

Part A
We have $f\left(x\right)=\left(x+3\right)^2-1$ . To solve for the x-intercept, we set f(x) equal to 0. That is
$\left(x+3\right)^2-1=0$

$\left(x+3\right)^2=1$

Take the square root of both sides,
$x+3=1$

$x=-2$

The x-intercept is (-2,0).

To solve for the y-intercept, we set x=0. That is
$y=\left(0+3\right)^2-1=3^2-1=9-1=8$

The y-intercept is (0, 8)

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have $g\left(x\right)=-2x^2+8x+3$ .
Factor out -2
$=-2\left(x^2-4x\right)+3$

Complete the square
$=-2\left(x^2-4x+4\right)+3-2\left(4\right)$

Simplify
$g(x)=-2\left(x-2\right)^2-5$

Part C
We have $h\left(t\right)=-16t^2+28t$ .
The maximum height is 12.25 feet after 0.875 seconds from the time of the jump. The dolphin will be back in the water after 1.75 seconds. The graph of the jump is shown in the photo.