Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
1: -13
Step-by-step explanation:
First, simplify the equation to -2y+10=36
Subtract 10 from both sides
-2y=26
Divide negative 2 from both sides
y=-13
The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.
<h3>How to solve the length?</h3>
Here, we have two similar right triangles, ΔABE and ΔCDE.
CD = 11 ft
DE = 2 ft
BD = 35 ft
First, find AB:
AB/11 = (35 + 2)/2
AB/11 = 37/2
Cross multiply
AB = (37 × 11)/2
AB = 203.5 ft
Then, apply Pythagorean Theorem to find AE:
AE = √(AB² + BE²)
AE = √(203.5² + 37²)
AE = 207 ft
Therefore, the length of the guy wire is 207 ft.
Learn more about Pythagorean theorem on:
brainly.com/question/654982