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timama [110]
3 years ago
6

Johnston Company wants to double production of Product X from 1,000 units to 2,000 units. The variable manufacturing cost per un

it is $10. The variable non manufacturing cost per unit is $20. There are no fixed costs. The selling price per unit is $50. What is the incremental cost of the proposed change?
A) $10,000B) $20,000C) $30,000
D) $60,000
Business
1 answer:
ratelena [41]3 years ago
7 0

Answer: C - $30,000

Explanation: Johnston Company wants to double production of Product X from 1,000 units to 2,000 units.

The variable manufacturing cost per unit is $10. The variable non manufacturing cost per unit is $20.

The selling price per unit is $50

To increase production by 1000 units

Total cost is $10 + $20 = $30

Total incremental cost = 1,000 * $30= $30,000

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How much interest you pay depends on_________
Damm [24]

Answer:

The Interest Rate and how much you owe.

Explanation:

If you have a rate of 10% a month

and you owe $100, the next month you owe $110

or if you owe $50, then next month you owe $55

6 0
2 years ago
Larry Ellison starts a company that manufactures high-end custom leather bags. He hires two employees. Each employee only begins
Degger [83]

Answer:

12.55 days

Explanation:

<em><u>Provided information </u></em>

Number of employees 2

Average production time=1.8 days

Standard deviation=2.7 days

Inter-arrival time= 1 day

Coefficient of variation= 1 day

Standard deviation of inter-arrival time= 1 day

The coefficient of variations

<u>Inter-arrival coefficient of variation </u>

C_{vi}=\frac {\sigma}{T} where \sigma is standard deviation of inter-arrival time, T is inter-arrival time and C_v is coefficient of variation of inter-arrival time

C_{vi}=\frac {1 day}{1 day}=1

<u>Production time coefficient of variation </u>

C_{vp}=\frac {2.7}{1.8}=1.5

<u><em>Total utilization time </em></u>

U=\frac {T}{n*T_i} where T is the time of production, n is number of employees, U is utilization, T_i is inter-arrival time

U=\frac {1.8}{2*1}=0.9

Therefore, utilization time by 2 employees is 0.9

<u>Expected average waiting time </u>

T_e=(\frac {T}{n*T_i})*0.5(C_{vi}^{2}+C_{vp}^{2})*(\frac{U^{\sqrt{2(n+1)}-1}}{1-U})

Where T_e is expected average waiting time and the other symbols as already defined

Substituting 1.5 for C_{vp}, 1 for C_{vi}, 0.9 for U, 2 for n, 1 for T_iand 1.8 for T

T_e=(\frac {1.8}{2*1})*0.5(1^{2}+1.5^{2})*(\frac{0.9^{\sqrt{2(2+1)}-1}}{1-0.9})

T_e=0.9*1.625*8.583709=12.55367 days  and rounding off to 2 decimal places we obtain 12.55 days

Therefore, expected duration between order received and beginning of production is approximately 12.55 days

7 0
2 years ago
Cheyenne is a manager at her company. She listens to an employee, Enu, voice his opinion about a policy that he disagrees with.
harkovskaia [24]

Answer: Professional benefits.

Explanation:

The illustration given in the question describes the professional benefit of listening. Cheyenne listened to her subordinates, which enabled her to identify the challenge her employees were facing and she was now able to solve the challenge, leading to a better work environment.

3 0
2 years ago
Which subjects does the Aspire test assess?
Nikolay [14]

Answer:

five subject areas: English, mathematics, reading, science, and writing

7 0
3 years ago
Kearney Inc. has a factory with the following characteristics: direct labor of $82056, direct materials of $52432 fixed overhead
frutty [35]

Answer:

The amount of cost from Pool A that is allocated to LQ6 is $7,802.

Explanation:

Since Pool A includes all variable overhead and uses direct labor as the allocation base, we can obtain the following from the question:

Direct labor = $82,056

Variable overhead = $146,362

Number of labor hours used by LQ6 = 162

Factory's labor costs per hour = $27

Therefore, we have:

Factory's labor cost of LQ6 = Number of labor hours used by LQ6 * Factory's labor costs per hour = 162 * $27 = $4,374

Variable over allocated to LQ6 from Pool A = (Factory's labor cost of LQ6 / Direct labor) * Variable overhead = ($4,374 / $82,056) * $146,362 = $7,801.83518572682

Rounding to whole number of $ as required, we have:

Variable over allocated to LQ6 from Pool A = $7,802

Therefore, the amount of cost from Pool A that is allocated to LQ6 is $7,802.

4 0
2 years ago
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