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Lady_Fox [76]
4 years ago
15

David divided 16.24 by 4 and got the quotient 4.6. Find the correct quotient and tell what you think David did wrong.

Mathematics
1 answer:
MrRissso [65]4 years ago
8 0

The answer is 4.06 David forgot to put a zero in the tenths place between 4 and 6 hundredths

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What makes a constant term differ from a term with a variable
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Variable varies or changes

constatant term doesn't change




examples
variables can change so example
x>10
x can be 11 or 33 or anythign bigger than 10

constants are no fun
they don't change an are boring, like
3 or 8, it just stays that way
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What is the additive inverse of th polynomial -9xy2+6x2y-5x3?
Norma-Jean [14]
Additive inverse of 9xy² + 6x²y - 5x³

-1(9xy² + 6x²y - 5x³) ⇒ (-1)(9xy²) + (-1)(6x²y) + (-1)(-5x³)

<span>-9xy² - 6x²y + 5x³ is the additive inverse of the given polynomial.</span>
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3 years ago
Whats the answer to the math problem -9n+10n
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Answer:

Just <em>N</em>

Step-by-step explanation:

Combine like terms to leave you with: <em>1n</em>

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Plzzz help need answer asap!! i will give brainliest!!​
SCORPION-xisa [38]

the top is adding 1 and the bottom is subtracting 5

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4 years ago
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The points (3,-2) and (2, 1) are both solutions to which inequality?
KIM [24]

(3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

<h3>How to determine the inequality?</h3>

The complete question is added as an attachment

The points are given as:

(3, -2) and (2, 1)

Next, we test the points on each inequality in the list of options.

So, we have:

<u>Option 1</u>

y > 1/2x + 2

Substitute (3, -2) and (2, 1) for x and y

-2 > 1/2 * 3 + 2 ⇒ -2 > 3.5 -- false

2 > 1/2 * 1 + 2 ⇒ 2 > 2.5 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y > 1/2x + 2

<u>Option 2</u>

y <= 3/2x - 1

Substitute (3, -2) and (2, 1) for x and y

-2 <= 3/2 * 3 - 1 ⇒ -2 <= 3.5 -- true

1 <= 3/2 * 2 - 1 ⇒ 1 < 2 -- true

Hence, (3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

<u>Option 3</u>

y >= 4x - 2

Substitute (3, -2) and (2, 1) for x and y

-2 >= 4 * 3 - 2 ⇒ -2 >= 10 -- false

2 <= 4 * 2 - 2 ⇒ 2 <= 6 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y >= 4x - 2

<u>Option 4</u>

y < -2x + 1

Substitute (3, -2) and (2, 1) for x and y

-2 < -2 * 3 + 1 ⇒ -2 < -5 -- false

2 < -2 * 2 + 1 ⇒ 2 < -3 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y < -2x + 1

Read more about inequality at

brainly.com/question/24372553

#SPJ1

7 0
2 years ago
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