Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
The value of the logarithm of ln(121) is <span>
4.7958 </span>Rounding <span>the answer to the nearest ten thousandth</span>
Answer:
alternate interior angles
Step-by-step explanation:
<1 is congruent to <2 by alternate interior angles
Answer:
whats ur question? theres no pic attatched
Step-by-step explanation: