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Elanso [62]
3 years ago
14

Solving equations with variables on both sides 7+9x=6x-2

Mathematics
2 answers:
vlabodo [156]3 years ago
8 0
7 + 9x = 6x - 2

ANSWER: x = -3
katrin2010 [14]3 years ago
3 0

Answer:

Here

Step-by-step explanation:

We move all terms to the left:

7+9x-(6x-2)=0

We get rid of parentheses

9x-6x+2+7=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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Read 2 more answers
The sum of two consecutive integers is 65. what are the two integers? show steps please.
Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

\triangle~\fbox{\bf{KEY:}}

  • Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

\longmapsto\sf{x+x+1=65}

Combine like terms:

\longmapsto\sf{2x+1=65}

Subtract 1 from both sides of the equal sign:

\longmapsto\sf{2x=64}

Divide both sides by 2:

\longmapsto\sf{x=32}

To find the second integer, subtract the first integer from the sum of the two integers:

\longmapsto\pmb{65-32}

\longmapsto\pmb{33}

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

7 0
2 years ago
What is the rule for the reflection?<br> Pls help me
Luda [366]
I want to say B
This is filler to answer
6 0
3 years ago
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