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PIT_PIT [208]
3 years ago
9

Which expression equals 24? a. (2 4)(3) b. (4 x 2)(3) c. (4 3) - 2 d. (4 - 2) 3?

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0
B. because 4×2 = 8×3 = 24 hope this helped :)
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Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

7 0
3 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
A trash can in the shape of a cylinder has a radius of 26 cm and a height of 39 cm. Which of the following is closest to the vol
My name is Ann [436]

Answer:

The volume of cylindrical trash is 82,782.96 cm³  .

Step-by-step explanation:

Given as :

The shape of the trash is cylinder

The radius of cylinder = r = 26 cm

The height of cylinder = h = 39 cm

Let The volume of cylindrical trash = v cm³

<u>Now, According to question</u>

volume = \Pi \times radius^{2}\times height

where \pi = 3.14

So, v = 3.14 × r² × h

Or, v = 3.14 × (26)² × (39)

Or, v = 3.14 × 26,364

∴  v = 82,782.96 cm³

So, volume of cylindrical trash = v = 82,782.96 cm³

Hence, The volume of cylindrical trash is 82,782.96 cm³  . Answer

5 0
3 years ago
Please help asap !!!!!! Which equation has one solution for x?
steposvetlana [31]
Question number b is the correct one
4 0
3 years ago
Read 2 more answers
What is 6.564671128 x 10^-7 meters converted into nanometers?
fomenos

Answer:

656.4671128 nanometer

Step-by-step explanation:

1 nano meter = 10 ^-9 meter

Now given 6.564671128 × 10^ -7 meters

so in nano meter ,

\frac{6564671128 times 10^-7}{10^9}

= 656.4671128 × 10^-9 meter

= 656.4671128 nanometer    Answer

3 0
3 years ago
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