Answer:
64
Step-by-step explanation:
As given, the diatance at any point after t seconds is given by
s(t)=16t²
At t=2 seconds then
s(2)=16*2²=16*4=64
Since we're not given the units, it may be feet, inches, meters, kilometers, miles etc. Therefore, the diatance is equal to 64 units
Answer:
4times tall
Step-by-step explanation:
Volume of the boxes = Base area × height
Volume of the first box V1 = A1h1
Given the base of the first box to be 5cm, the base area:
A1 = 5cm×5cm = 25cm²
Volume of the first box V1 = 25h1... 1
Similarly, volume of the second box
V2 = A2h2
Given the base of the second box to be 10cm, the base area:
A2= 10cm×10cm = 100cm²
Volume of the second box
V2 = 100h2... 2
If the two boxes have the same volume, then V1 = V2
25h1 = 100h2
divide both sides by 25
25h1/25 = 100h2/25
h1 = 4h2
Since the height of the smaller box is represented as h1, then the height of the smaller base is 4 times tall.
yes. The zero to the left of the decimal point does not affect the overall value of the problem when removed, since it is zero.
Half-life, h = 13 hours
Mass initial, a = 38 g
B=base for half-life = 2
(a)
I(t)=a*B^(-t/h)=a*(B^(1/h)^(-t)=a*(B^(-1/13))^t
Substituting values,
I(t)=38*(2^(-1/13))^t
a=38 g
b=2^(-1/13)=0.9480775 (approximately)
=>
I(t)=38*0.9480775^t
(b) I(t)=7
solve
I(t)=7=38*0.948077^t
Take log on both sides and solve for t
t=log(7/38)/log(0.948077)
=31.727 hours.
Check: I(31.727)=38*9.948077^(31.727)=7.000 g ok
