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salantis [7]
3 years ago
13

15 POINTS PLEASE HELP ME

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0
1.2/1.8=10/x
Find 1.2 over 1.8 and apply that by multiplying the answer by 10. Because it’s the same ratio
You might be interested in
How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0
3 years ago
PLEASEEE HELP AND SHOW WORK​
Verdich [7]
I mean it should be 7 cause 2 angles are congruent.
6 0
3 years ago
Please try your best and show your work and I will give brainliest!
dimulka [17.4K]

Answer:

Part A: impossible

Part B: Either equal or blue

Part C: 9 green and 2 blue were added

Step-by-step explanation:

Part A:

The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.

Part B:

I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.

Part C:

The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.

I hope this helps and please mark me as brainliest!

5 0
2 years ago
Does (9,8) make the inequality y < 10×+8 true
ExtremeBDS [4]

Answer:

Yes, the point makes the inequality true

Step-by-step explanation:

y < 10x+8

Substitute x =9 and y=8 into the inequality

8 < 10*9+8

8<90+8

8<98

This is true so the point makes the inequality true

7 0
4 years ago
Read 2 more answers
Find the equation for the line that passes through the point (1,3), and that is perpendicular to the line with the equation y +
Marianna [84]

Step-by-step explanation:

the slope of a line function is always the factor of x.

in our case : -1/4

it is the ratio y/x indicating how many units y changes, when x changes a certain amount of units.

in our case y decreases by 1 for every x increase by 4.

now, the perpendicular slope simply changes x and y upside-down and flips the sign.

in our case it is : 4/1 = 4

so, the line function in point slope form is then (using the new slope and the point coordinates)

y - 3 = 4(x - 1)

5 0
3 years ago
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