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Ivan
2 years ago
10

HELLLLLLLPPPP PLZZZZZZZZZZZZ THIS IS A TEST

Mathematics
2 answers:
Alex777 [14]2 years ago
6 0

Answer:

Decimal=0.76 proportion=76%

Step-by-step explanation:

19/25 let's find the decimal first

long division:

25|19

25 goes into 1, 0 times so;

    0

25|19

   -0

     19

25 goes into 19 0 times so;

    00.

25|19.0

   -0

     19

     -0

     190

25 goes into 190 7 times so;

    00.7

25|19.00

   -0

     19

     -0

     190

    -175

       150

25 goes into 150  6 times so;

    00.76

25|19.00

   -0

     19

     -0

     190

    -175

       150

      -150

           0

now 19/25 as a proportion;

19........x

---- = ------

25.....100

25*4=100 so 19*4=x

19*4=76 so x = 76

and 76/100=76%

Reika [66]2 years ago
5 0

Answer:

76%= Decimal: 0.76 and proportion 76%

Step-by-step explanation:

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X + y = 8 <br> how do i solve for x
IgorC [24]

Answer:

x = 8 - y

Step by step explaination:

==>x + y = 8

==> x = 8 - y

==> substract the value

==> Done

5 0
2 years ago
4) Write the quadratic equation of the following in vertex form: vertex (-1,3) and passes through (1,-5)
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You will have to set up a system of equations
4 0
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Write and solve an inequality that means a number<br> plus four is greater than or equal to twelve.
Stella [2.4K]
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4 0
3 years ago
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Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
2 years ago
What is 20x30 i need the answer nowwwwwwwwwwwwww
cestrela7 [59]

Answer: 600

<u>Step-by-step explanation:</u>

   20    x    30

= 2 x 10 x   3 x 10

= 2 x 3   x  10 x 10

=    6      x     100

=         600

6 0
3 years ago
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