<span><span><span>(<span>5/2</span>)</span>^2</span>+<span><span>3^3</span>/4</span></span><span>
</span><span>=<span><span>25/4</span>+<span><span>3/</span>4-3</span></span></span><span>
</span><span>=<span><span>25/4</span>+<span>27/4</span></span></span><span>
</span><span>=13</span>
Answer:
F(2, 11/2)
Step-by-step explanation:
The expression:
(x-2)² = 10(y - 3)
can be rewritten in the vertex form as follows:
(x-2)² = 10y - 30
(x-2)² + 30 = 10y
1/10(x-2)² + 3 = y
General vertex form is:
y = a(x-h)² + k
then, the vertex is locate at (h, k). In this case the vertes is (2, 3), and <em>a </em>= 1/10
The focus of a parabola is located ar F(h, k+p), where <em>p</em> = 1/(4a). Replacing into these equations:
p = 1/(4*1/10) = 5/2
F(2, 3+5/2) = F(2, 11/2)
