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svlad2 [7]
3 years ago
14

Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be model

ed by (x-2)^2=10(y-3), where x and y are measured in inches. Where is the focus of the flashlight?
Mathematics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

C is the answer

Step-by-step explanation:

I'm never wrong.

Tomtit [17]3 years ago
6 0

Answer:

F(2, 11/2)

Step-by-step explanation:

The expression:

(x-2)² = 10(y - 3)

can be rewritten in the vertex form as follows:

(x-2)² = 10y - 30

(x-2)² + 30 = 10y

1/10(x-2)² + 3 = y

General vertex form is:

y = a(x-h)² + k

then, the vertex is locate at (h, k). In this case the vertes is (2, 3), and <em>a </em>= 1/10

The focus of a parabola is located ar F(h, k+p), where <em>p</em> = 1/(4a). Replacing into these equations:

p = 1/(4*1/10) = 5/2

F(2, 3+5/2) = F(2, 11/2)

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